00:01
Once again, welcome to a new problem.
00:05
This time we're dealing with sets.
00:07
So a set is pretty much a group of elements.
00:14
So a set is a group of elements.
00:16
For example, a can be a set of 1, 2, 3, 4, and 5.
00:23
And b can also be a set of 1, 2, and 3 such that b, is a subset of a in this context.
00:41
So think about our new problem and our goal is to determine whether the given set or given sets are power sets.
01:16
Whether the given sets are power sets.
01:28
The given sets determine whether the given sets are power sets of existing sets, where a and b are elements of the set.
01:48
So a and b are elements of the set.
01:51
If you think about it, if you think about it, this represents an empty set with no elements.
02:09
So this is an empty set with no elements.
02:13
And of course, p of s is the power set, is the power set which consists of all subsets of s including including s itself.
02:35
All subsets of s including s itself.
02:39
So in the first problem part a, we have every given set s has at least one subset, has at least one subset.
03:22
Has at least one subset.
03:24
And every set has the empty set.
03:37
And so we're going to say that the power set, the power set, of s therefore contains at least one element...