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Problem

Determine whether each equation has the given ord…

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Deandre J.

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79 Problem 80 Problem 81 Problem 82 Problem 83 Problem 84 Problem 85 Problem 86 Problem 87 Problem 88 Problem 89 Problem 90 Problem 91 Problem 92 Problem 93 Problem 94 Problem 95 Problem 96 Problem 97 Problem 98 Problem 99 Problem 100 Problem 101 Problem 102 Problem 103 Problem 104 Problem 105 Problem 106 Problem 107 Problem 108

Problem 25 Easy Difficulty

Determine whether each equation has the given ordered pair as a solution.
$y-6 x=12 ;\left(\frac{5}{6}, 7\right)$

Answer

No

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Video Transcript

all right for this problem were asked to determine if the point 5/6 comma seven is a solution to the equation. Why minus six X is equal to 12. In order to solve this, we will plug in the point into the equation. We recognize that points are in the form X comma y. And so that tells us that we were place every X in the equation with a 5/6. And then we replaced every why in the equation with a seven so right that bottom why were replaced with seven minus six x we replace the X with a 5/6 equals 12. And so now we simplify the left side seven minus six times 5/6. The six is cancelled because there's a six and the numerator and the denominator, and we get a five equals 12. Now we further simplify the left side. Seven minus five is too, which is equal to 12. Now we know that too is not equal to 12 because they're not the same number. And so that tells us that the point 5/6 comma seven is not a solution to the equation.

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Alan S. Tussy, R. David Gustafson

Elementary and Intermediate Algebra

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