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Determine whether each equation is linear or not. Then graph the equation by finding and plotting ordered pair solutions. See Examples 3 through 7.$$y=2 x^{2}$$

$\begin{array}{llllllll}x & -3 & -2 & -1 & 0 & 1 & 2 & 3 \\ y & 18 & 8 & 2 & 0 & 2 & 8 & 18\end{array}$

Algebra

Chapter 3

Graphs and Functions

Section 1

Graphing Equations

Functions

Missouri State University

Idaho State University

Lectures

01:43

In mathematics, a function…

03:18

02:57

Determine whether each equ…

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02:37

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02:43

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02:14

02:28

03:01

in this problem were given the equation Y equals two x squared, and we need to determine if that equation is linear. Linear equations are to be written as Why equals gimmicks plus B on the one thing I noticed in a linear equation that are given equation has is a two as an exponents in a linear equation, your eggs actually has an exponents of one not of anything else. So this tells May that this is not linear. So let's go ahead and less fun points for X and why, So that we can graph and prove that this is not linear for X. We're gonna use the points negative to negative 101 and two. So if we're gonna put these numbers in place of eggs, let's start with why equals two times negative two squared. So we're actually going to square the negative to first, so I'm gonna have to times a negative to squared is four. So two times four is eight. Next. So how Why equals two times negative. One squared negative one squared is one. So to Tom's, one is to why equals two times zero squared. Well, zero squared is still zero. So two times zero is zero. Why equals two times one squared, one squared is one and two times one is two And why equals two times to swear? Two squared is four and two times four is eight. So these are the points I'm going to graph, So we'll start where X is negative. Two. Why is eight then exits? Negative one. Why is positive too? We'll have 00 which is the Origin X is one wise positive, too. And then X is to y is positive. Eight. So here, Comptel Because my points when I draw the line or even without Kalanick until my points don't lie on the same line in a straight line so I can see that this is not a linear equation.

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