00:01
All right, so number four, we're going to check to see if part a and b are solutions to the system of linear equations.
00:08
So in order to do that, i am going to take my point and plug in the x and y values and see if it gives me a true statement in my equation.
00:19
So for part a, my x is negative 2 and my y is negative 4.
00:24
So i'm going to check the first equation and see if when i plug in my x and y values, if it's true.
00:30
So 2 times negative 2, which is my x, minus 3 times negative 4, which is my y.
00:38
And we're going to see if that comes out to 8.
00:41
So 2 times negative 2 is negative 4.
00:45
Negative 3 times negative 4 is positive 12.
00:50
So negative 4 plus 12 is 8.
00:56
Therefore, it works for the first equation, which means i need to check my second equation and see if that point is good in my second equation as well.
01:06
It is on my first line and my second line, then that means it is a solution to the system of equations, which would represent the intersection point on a graph.
01:16
So checking my second equation, i have negative 2 minus 2 times negative 4, and we want to see if that is equal to 6.
01:26
So negative 2, and then if i take negative 2 times negative 4, that's going to give me a positive 8.
01:33
So negative 2 plus 8 is 6.
01:36
So since that's true for...
01:37
Both of the equations, that means that negative 2, negative 4, is a solution to the system of linear equations...