00:02
Given the inequality, negative 1 is less than 3 minus x divided by 2 is less than or equal to 1.
00:08
We're going to determine whether or not x equals negative 1, x equals square width of 3, x equals 1, and x equals 5 are solutions to this inequality.
00:18
We're going to do that through substitution and seeing if the statement we get is in fact true.
00:23
So for x equals negative 1, we get negative 1 is less than 3 minus negative 1 over 2 is less than or equal to 1.
00:32
1.
00:33
Negative 1 is less than 3 minus negative 1 is 3 plus 1.
00:37
So we get 4 over 2 is less than or equal to 1.
00:42
Negative 1 is less than 2 is less than or equal to 1.
00:46
Negative 1 is in fact less than 2.
00:48
However, it is not less than or equal to 1.
00:51
So negative 1 does not work as a solution to this inequality.
00:55
Our second one is x equals the square of 3.
00:58
Negative 1 is less than 3 minus the square to 3 over 2 is less than or equal to 1.
01:06
Negative 1 is less than 3 minus the square to 3 is roughly 0 .76 over 2 is less than or equal to 1.
01:17
Negative 1 is less than 0 .76 divided by 2 is 0 .38 is less than or equal to 1.
01:26
Negative 1 is in fact less than 0 .38 and 0 .38 is in fact less than or equal to 1...