Question
Determine whether each $x$ -value is a solution (or an approximate solution) of the equation.$3 e^{x+2}=75$(a) $x=-2+e^{25}$(b) $x=-2+\ln 25$(c) $x \approx 1.219$
Step 1
Step 1: Substitute $x=-2+e^{25}$ into the equation $3 e^{x+2}=75$: \[3 e^{(-2+e^{25}+2)}=75\] which simplifies to: \[3 e^{e^{25}}=75\] Divide both sides by 3: \[e^{e^{25}}=25\] This is not true, so $x=-2+e^{25}$ is not a solution. Show more…
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