00:01
For this problem, we are given the vector field, f equals y times e to the power of negative x, i, plus e to the power of negative x, j, plus 2z, k.
00:11
We are asked to determine if the field f is conservative.
00:15
So we can use the theorem that i have a reminder of over to the side here.
00:18
First requirement for it to be conservative is that it has continuous partial derivatives, which we can see trivially that is true.
00:25
So we need to see if the curl of f is going to equal the zero vector.
00:29
So we can set up our determinant equation here.
00:33
Oops, i need a cross in there.
00:35
Del cross f is going to equal, now the determinant of the matrix, i vector, d by dx, or just dx as i write it for shorthand, y to the power of negative x.
00:46
Then for the next column, it will be j vector, dy, e to the power of negative x, and then for the k column, we'll have dz and 2z...