Question
Determine whether the improper integral diverges or converges. Evaluate the integral if it converges.$$\int_{-\infty}^{-1} \frac{1}{x^{2}} d x$$
Step 1
Step 1: First, we rewrite the integral as a limit: $$ \int_{-\infty}^{-1} \frac{1}{x^{2}} d x = \lim_{a \to -\infty} \int_{a}^{-1} \frac{1}{x^{2}} d x $$ Show more…
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