Question
Determine whether the lines $L_{1}$ and $L_{2}$ are parallel, skew, or intersecting. If they intersect, find the point of intersection.$L_{1}: x=5-12 t, \quad y=3+9 t, \quad z=1-3 t$$L_{2}: x=3+8 s, \quad y=-6 s, \quad z=7+2 s$
Step 1
The direction vector of a line is given by the coefficients of the parameters in the parametric equations of the line. For $L_{1}$, the direction vector is $(-12, 9, -3)$ and for $L_{2}$, the direction vector is $(8, -6, 2)$. Show more…
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Determine whether the lines $L_{1}$ and $L_{2}$ are parallel, skew, or intersecting. If they intersect, find the point of intersection. $L_{1} : x=-6 t, \quad y=1+9 t, \quad z=-3 t$ $L_{2} : \quad x=1+2 s, \quad y=4-3 s, \quad z=s$
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Determine whether the lines $ L_1 $ and $ L_2 $ are parallel, skew, or intersecting. If they intersect, find the point of intersection. $ L_1 : x = 5 - 12t , y = 3 + 9t , z = 1 - 3t $ $ L_2 : x = 3 + 8s , y = -6s , z = 7 + 2s $
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