The normal vector of a plane is simply the coefficients of x, y, and z in the equation of the plane. So, for the first plane $x+4y-3z=1$, the normal vector $\vec{n_1}$ is $(1, 4, -3)$. For the second plane $-3x+6y+7z=0$, the normal vector $\vec{n_2}$ is $(-3, 6,
Show more…