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Determine whether the relation defines to be a function of . If a function is defined, give its domain and range. If it does not define a function, find two ordered pairs that show a value of that is assigned more than one value of . See Example 2.$$\begin{array}{|r|r|}\hline x & {y} \\\hline 6 & {0} \\{-3} & {-8} \\{1} & {9} \\{5} & {4} \\\hline\end{array}$$
Yes; domain: $\{-3,1,5,6\}$;range: $\{-8,0,4,9\}$
Algebra
Chapter 3
Graphing Linear Equations and Inequalities in Two Variables; Functions
Section 8
An Introduction to Functions
Graphs and Statistics
Equations and Inequalities
Linear Functions
Systems of Equations and Inequalities
Campbell University
Baylor University
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this problem. We're given the table of values and we're being asked to term weapons. This relation is a function well. Remember, if it's a function that means each X value will be assigned to, it's all too on. Lee won. Why Value? So let's take a look at our table. If you know this, every single X value is only a sign toe one. Why value? Therefore, this is a function Now. Our directions tell us that if it's a function, we need to find a domain and range. So let's start with the domain. Well, remember, the domain is the set of all of the first components. Well, the first component is just another way of saying the X values in the relation. So in this particular case, our domain is the set of six negative 31 and five. Now what's next? Fine. The range. Well, the range is the set of all of the second components in the relation well, the second component is really just r y values. So for us, our range is going to be zero negative. Nine and four
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