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Determine whether the relation defines to be a function of . If a function is defined, give its domain and range. If it does not define a function, find two ordered pairs that show a value of that is assigned more than one value of . See Example 2.$$\{(-2,7),(-1,10),(0,13),(1,16)\}$$
Yes; domain: $\{-2,-1,0,1\}$; range: $\{7,10,13,16\}$
Algebra
Chapter 3
Graphing Linear Equations and Inequalities in Two Variables; Functions
Section 8
An Introduction to Functions
Graphs and Statistics
Equations and Inequalities
Linear Functions
Systems of Equations and Inequalities
Missouri State University
McMaster University
Baylor University
University of Michigan - Ann Arbor
Lectures
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and this problem were given the seven ordered pairs. That represents a relation, and what we want to do first is determined whether this relation represents a function well, if it's a function that means every X value will be assigned to exactly one. Why value? So let's take a look. Well, each X value is assigned to only one y value, and negative, too, is only assigns a seven. The negative one is only assigned to Tek. Zero is only assigned the 13 and the one is only assigned to 6 60 Therefore, this relation is a function Now. Our directions tell us if it's a function to determine the domain in the range. So let's start with the domain. Well, though domain represents the first components for each of our order pairs. So in that case, it would be negative too negative 10 and positive one. So our domain is the set off. Negative too negative. 10 and one. Now we need to find the range. Well, the range represents the second component each pair, So that will be 7 10 13 and 60. So our range will be the set off. 7 10 13 and 16
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