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Determine whether the relation defines to be a function of . If a function is defined, give its domain and range. If it does not define a function, find two ordered pairs that show a value of that is assigned more than one value of . See Example 2.$$\begin{array}{|l|r|}\hline x & {y} \\\hline 3 & {4} \\{3} & {-4} \\{4} & {3} \\{4} & {-3} \\\hline\end{array}$$
$\mathrm{No} ;(3,4),(3,-4)$ or (4,3),(4,-3)
Algebra
Chapter 3
Graphing Linear Equations and Inequalities in Two Variables; Functions
Section 8
An Introduction to Functions
Graphs and Statistics
Equations and Inequalities
Linear Functions
Systems of Equations and Inequalities
Oregon State University
McMaster University
Harvey Mudd College
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this problem. We're given a table of values that represents a relation and were first being asked to fund figure out whoever this relation represents. A function well, remember, ah, function means that every X value is assigned to a different wide value. Well, let's take a look at our table. What's actually look at that first or two pair of 34 So three is assigned to four, but in the order pair below it three is assigned to negative for. Therefore, this cannot be a function because that X value of three is getting assigned to two different y values. So again, this is not a function. So our direction's say that if it's not a function to pick out two or repairs where the next value is getting assigned to more than one y value. Well, we've essentially already done this. We can say that ordered pair 34 because three is assigned to four and for the ordered pair three negative for because three is also assigned to negative for you can if you also know this. The same is true for our the order pairs for three and four negative three so you could have also answered this part by the oId repairs for three and for negative three because again, there's an X value getting assigned to two different wide values.
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