00:01
Hello and welcome.
00:02
We're looking at chapter 2, section 1, problem 23.
00:07
We're asked to determine the convergence of this sequence here.
00:13
It's worth looking back at our laws of logarithms because they definitely come in handy for this problem.
00:25
So one of the laws of logarithm is if you're subtracting two logs, you can combine them in one log, one logarithm, as a division of the arguments of what's inside here.
00:41
This would be 2n squared plus 1 over n squared plus 1.
00:49
So if we take the limit of that new way of writing it, what we can do now using the laws of limits, the limit of this natural logarithm is actually going to be the same as the natural logarithm of the limit.
01:19
We can basically bring that limit inside.
01:22
The log riddle.
01:30
Now if we do that, we're just taking a limit of a polynomial over a polynomial, and we use the same trick we always do when we have that situation.
01:41
We divide the numerator and denominator by the highest powered term in the denominator.
01:49
So that would be n squared.
01:50
So i'm going to multiply the top by one over n squared.
01:53
That's the same as dividing...