00:01
So for this problem, we are given a sequence described by the equation a7 is equal to e to the n plus e to the negative n divided by e to the 2n.
00:13
So let me just erase this.
00:16
It should be e to the 2n.
00:19
Oh, let me use a red than instead.
00:23
It should be e to the 2n minus 1.
00:28
And take note from this expression, e to the negative n is the same as 1 over 8.
00:37
E to the end.
00:40
Okay.
00:43
Now, what i wanted to emphasize here is that as n approaches to infinity, e to the end also increases more and more.
00:54
It approaches to infinity.
00:57
Taking that e is a specific constant value that is not equal to one.
01:04
It's actually greater than one.
01:06
And so as you increase its exponent positively more and more, its equivalent value is increasing more and more as well...