00:01
The a -n terms that we're looking at is n squared times e to the minus n.
00:06
So another way of writing this is n squared over e -to -the -n.
00:11
So we should know already that this is going to go to zero because we have polynomial growth in the numerator, and we have exponential growth in the denominator.
00:21
You can also prove it using lopatal's rule.
00:31
This will be an easy thing to work with for lopatal's rule.
00:34
So we're allowed to use lopatil's rule when we have something that would give us in favor, over infinity or 0 over 0 if we were to just plug in the value of n here.
00:45
So if we were just to plug in n equals infinity, we would get infinity over infinity here, right? that's something that we're not actually allowed to do because infinity over infinity is indeterminate form.
00:56
But if we are in that type of situation, we're allowed to use lopatal's rule, which means that we take the derivative of the top part, and we divide by the derivative of the denominator...