00:01
Hello, so here we have that a sub n is equal to 2n minus 3 divided by 3n plus 4.
00:06
So now we consider the function f of x, which is equal to, well, 2x minus 3 over 3x plus 4 and then take the derivative by the quotient rule.
00:16
So then f prime of x would be equal to, well, the bottom times the derivative of the top minus the top times the derivative of the bottom, all at the bottom by the bottom square.
00:27
So that gives us why 3x plus 4 times 2 gives us a 6x plus 8, and then minus 2x minus 3 times 3 gives us a minus 6x plus 9, and then all divided by the bottom squared.
00:46
So that's 3x plus 4 quantity squared, which gives us the top numerator just becomes 17.
00:53
So we get 17 over the quantity 3x plus 4 squared.
01:00
And this is going to be well positive, right? numo is always 17.
01:04
This is always going to be greater than zero for all x.
01:07
Therefore we have that f is going to be an increasing function...