00:01
For this problem, our sequence is 1 over 2k.
00:04
Now, i'll note that, first of all, if we have that k is always greater than or equal to 1, then that means that 2k will always be greater than or equal to 2, and so 1 over 2k will always be less than or equal to 1 over 2.
00:22
So we have that this is bounded above.
00:27
Then we also have that the limit, as k approaches infinity, of 1 over 2 ,000, 2k is going to be equal to 0.
00:36
So we additionally have that this is bounded below.
00:40
Regarding monotonicity, it's pretty easy to see that ak over ak plus 1 be equal to 1 over 2k times 2k or times 2k plus 2 over 1, which would then be just equal to k plus 1 over k, which is always going to be greater than one...