00:02
All right, we're looking at chapter 2, section 3, question 44a.
00:17
All right, so this is not a basis for 3 space, because you need three, three linearly independent vectors, and there's only two.
01:07
Now, for b, this is also not a basis for three space.
01:26
And what we have for vc equals zero here is the following matrix, 1, 2, 401, negative 3, negative 1, 4, negative 1, 0 ,000, 0 ,000.
01:45
0.
01:53
And so what we're going to, oops, let's change this for a second.
02:02
1, 2, 4, 1, 3, 1.
02:14
And so when you solve for this, this is going to equal the identity matrix with zeros here.
02:25
So what that means we have c sub 1 equals c sub 2 equals c sub 3, which equals 0.
02:37
And therefore we know that v sub 1, v sub 2, v sub 2, v sub 3, are independent.
02:57
So we can say that v...