We will take the derivative of the right side of the first result, which is $\frac{1}{4}(x+1)^{4}+C$.
Using the chain rule, we get:
$$
\frac{d}{dx} \left(\frac{1}{4}(x+1)^{4}+C\right) = \frac{4}{4}(x+1)^{3} \cdot \frac{d}{dx}(x+1) = (x+1)^{3}
$$
This is exactly
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