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Determine which of the matrices in Exercises $1-6$ are symmetric. $$\left[\begin{array}{rrr}{-6} & {2} & {0} \\ {2} & {-6} & {2} \\ {0} & {2} & {-6}\end{array}\right]$$

Yes, Transpose(A) $=A$

Algebra

Chapter 7

Symmetric Matrices and Quadratic Forms

Section 1

Diagonalization of Symmetric Matrices

Introduction to Matrices

McMaster University

Baylor University

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were given a matrix and were asked to determine if it's symmetric. The Matrix A is negative. 6 to 0 to negative 62 zero to negative six. A transpose is equal to the Matrix. Dagnall stays the same. Negative six. Negative six. Negative six. And then we exchanged two with two zero with zero. And again we exchange two with two. And so we see that a is equal a transpose. So it follows that a is a symmetric matrix.

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