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Question

Determine which values of $x$ and $y,$ if any, are not permissible. In Exercise $27,$ explain your answer.
$$f(x, y)=\sqrt{x^{2}-x^{2} y+y^{2}-y^{3}}$$

Tyler Moulton · Accepted Answer

we want to identify for which values of X and Y are function F is defied. Our functional alphabet is F of x. Y equals x squared minus x squared Y plus y squared by this wife. You. This question is challenges the answer for which X and Y does have a valid output. So this essentially then a domain problem. Remember that for domains is defined for the three conditions here where a the denominator of our functional equals zero. For any argument under a square root, the argument must go to the zero and see for any natural algorithm the argument of the natural log or for the log is greater than zero. Thus we see that there is no denominator and there is no longer rhythm here but we do have to satisfy will be so from ruby we get that X squared minus x squared y plus y squared minus Y. You must be greater than zero. Thus we finished analyzing this function and we have that F is defined for all X Y satisfying the highlighted condition.

Amrita Bhasin · Answer

the first thing they could do is put all the terms containing why on the left and all the terms containing X on the right. Now that we&#x27;ve done this, we can take the integral and write this as y over, too. I scored over two equals X before or four plus acts, and now we know there&#x27;s gonna be a pussy over here. So you plug in. Wyck was, too, and X equals one to solve for C and we get C equals 3/4 of plus C weaken right plus 3/4. Now, given this solving for why we get Wyck was plus or minus, there&#x27;s two answers. The square of 27 over too.

Sriram Soundarrajan · Answer

Hello, Are you going? Bazaar Problem number 23 here The given faction have is given by square root off three access to fight in the Y, minus seven excusable late So foster different treated respect tricks We will get like bye bye a little three Xs terrifying into away by us seven x cubed What in do 15 existed for in the way minus good dealer, paper square. But action with respect to buy you don&#x27;t get like Martin play truly three existed five in Dubai my anus seven excuse by in tow three existed. Five minus seven Excuse

Ali Soave · Answer

it was trading at the Y. Going by itself will start off by subtracting X from both sides. Why cubed is equal to Tony seven minus X. Then we&#x27;ll take the cube root of both sides. Queudrue. These cancel out and why is equal to the cubed root of 27 minus sex? Because every input, every number that we plug in for X will be equal to exactly one output. And yes, this is

Aditya Balasubramanian · Answer

we&#x27;re here. We have two different things that we want to find for which values of X and Y make these things equals. So let&#x27;s just simplify, but see what we got, right? So the square root of X squared right in the fourth is just X squared to the 1/2 writing for to 1/2. That just means that we have X. Why squared right here in the 1st 1? And if you do the same thing with the 2nd 1 you&#x27;ll get X Y squared once again. But now we have to pay attention to those positives and negatives, right? We should look att ex cause ex has an even explode in the first sort of expert in the other one. So let&#x27;s plug in negative one for X. We can keep two for why the number two for why in both ones. But let&#x27;s put a negative one for X and you&#x27;ll get a negative one. So let&#x27;s just write down what I&#x27;m doing right? This is These are the numbers that I&#x27;m using so negative one squared is just one times two to the fourth to the fourth ends up being 16 so it&#x27;s squared of 16 just four, right? So top one equals for top equals four and the bottom equal. So if you put one negative one cube 2 to 6 to six before times negative one is negative. 64. So you have the cube root of negative 64. That is negative for us. I think this solution only works when X is greater than zero. Because you have diff you haven&#x27;t even explain it. And you haven&#x27;t on exponents. You need to account for that with your positives and negatives. So oh, real numbers off. Why all riel numbers of X where X there&#x27;s greater than zero or positive, and that is it.

Amy Jiang · Answer

So let&#x27;s reduce what&#x27;s inside irritable. So let&#x27;s work with my first term. We have 28. This is two times 14 and 14. It&#x27;s two times seven so we can pull out too. And then well, no. This is why there are three. Which is why I survived two times. Why? So we can also pull out of why. So it&#x27;s right this So we still have an X. We can pull out too. So we have two x y and then we have the square roots. We have a seven remaining, an X x and why it is the seven x y. And now for 63. Well, let&#x27;s see 6 63 is three times 2121 is three times seven. We can pull out of three, so we have three. Why? And then we&#x27;ll notice here actually that we haven&#x27;t executed. So that&#x27;s X squared Times X. So we can actually pull out this X here. So we have a three x minute by it shouldn&#x27;t be a plus on the square root with remaining a seven x and a y. So we see that these two are the same terms for our light terms. So let&#x27;s combine them. So we have to post three. That&#x27;s five x wide square root of seven X. Why?

Problem

Determine which values of $x$ and $y,$ if any, ar…

Problem 27 Easy Difficulty

Determine which values of $x$ and $y,$ if any, are not permissible. In Exercise $27,$ explain your answer.
$$f(x, y)=\sqrt{x^{2}-x^{2} y+y^{2}-y^{3}}$$

Answer

$y \leq 1$

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$y \leq 1$

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Allyn J. Washington, Richard S. EvansBasic Technical Mathematics with Calculus

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