Question
Determining the Vertex and Intercepts of a Quadratic Function.a. Find the vertex.b. Find the $y$ -intercept.c. Find the $x$ -intercept(s), if they exist.d. Use this information to graph the function.$$y=-x^{2}-2 x+3$$(graph can't copy)
Step 1
In this case, $a = -1$ and $b = -2$. So, the x-coordinate of the vertex is $-\frac{-2}{2(-1)} = -1$. Substituting $x = -1$ into the function gives $f(-1) = -(-1)^2 - 2(-1) + 3 = 4$. Therefore, the vertex of the function is $(-1, 4)$. Show more…
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