00:02
This is the answer to chapter 12, problem number 69, from the smith organic chemistry textbook.
00:10
And in this problem, we're asked to synthesize four molecules from four given starting materials.
00:19
And we're told we can use any other required reagents.
00:23
So to start with, in a, we need to get from this starting material here, this alken, to a carboxylic acid, but all that we really need to do is add that carboxylic acid.
00:41
We're not changing anything about the other carbons in the molecule or anything.
00:46
So a good way to start is going to be to install an alcohol, so a terminal, a primary alcohol here.
00:56
And we can do that.
01:04
Okay, there we go.
01:05
Sorry.
01:07
We can do that by using, for example, bh3 followed by hydrogen peroxide and hydroxide ion.
01:27
And so that's going to install the alcohol, the primary alcohol.
01:32
So if we were to use, for example, sulfuric acid and water, that would actually install the secondary alcohol instead.
01:41
But what we want here is this primary alcohol.
01:47
Okay.
01:48
And so there we go.
01:50
And then from here, it's just a simple chromium oxidation.
01:55
So we can use chromium trioxide, sulfuric acid, help if i wrote the right reagents.
02:10
So sulfuric acid and water.
02:12
And so that's going to, remember, that's going to oxidize a primary alcohol like this all the way up to the carboxylic acid.
02:22
So if we were used like pcc, that would stop at the aldehyde, but we want the carboxylic acid here.
02:31
And so chromium trioxide is a good reagent to use here.
02:37
C -o -o -h.
02:40
Okay.
02:40
And so there we go.
02:41
That's the product that we were asked to make for a.
02:43
So then for b, we're going to do something somewhat similar.
02:49
So we're starting from the alcohol here, the primary alcohol.
02:53
But in this case, we actually want the ketone.
02:57
So we want to go from this primary alcohol to a secondary alcohol on the next carbon over.
03:03
And then we'll oxidize that.
03:06
And rather than having a carboxylic acid, we'll have a ketone.
03:10
And so we can be, well, so let me draw the starting material.
03:14
So ch3, ch2, ch2, ch2, ch2, ch2oh.
03:27
Okay, so the first thing we need to do is dehydrate this primary alcohol.
03:33
And so concentrated sulfuric acid and water will dehydrate an alcohol.
03:40
So we now are at this alken.
03:43
And so we can again use so i guess the thing i forgot here is heat right so we need to heat in alcohol in concentrated acid and a little bit of water and that will get us our dehydration so if instead we use more dilute sulfuric acid here and so more water and no heat.
04:21
So now this is going to re -ad that alcohol, but it's going to be the secondary alcohol this time.
04:39
So there we go.
04:41
And then from here, we can just do an oxidation.
04:45
We could use chromium trioxide again, but i'm just going to use pcc.
04:51
Pcc is easy.
04:54
C .h3, ch2c.
04:57
C .h2c.
04:59
Ketone, ch3.
05:02
Okay, and so there's our final product for b.
05:07
So c on the next page here.
05:12
So in c, we need to go from cyclohexene to this molecule with a ketone and a triple bond in it.
05:27
And so a good way to start here.
05:29
So here is our starting material...