00:02
This is the answer to chapter 12, problem number 57 from the smith organic chemistry textbook.
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And this problem asks us to consider dha, which we're told is a fatty acid, invertebrate brains and stuff.
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And basically, we're given a hydrogenation product and the oz analysis products.
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And then we're asked to determine the structure.
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And so i've just rewritten that data here.
00:41
And so first looking at the hydrogenation data, we see that this is basically just a 22 carbon fatty acid.
00:51
So there is a methyl group at one end, 20 ch2s in a row, and then a carboxylic acid when we, when we hydrogenate dha.
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When we oxidatively cleave dha, we get three types of pieces.
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So we get a three carbon aldehyde.
01:16
We get five equivalents of a three carbon dialdehyde.
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And then we get one equivalent of a four carbon chain with an aldehyde on one end and a carboxylic acid on the other.
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And so the first and third molecules here are end pieces.
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And then these five three carbon dialdehyde sections that we have are just repeats in the middle.
01:52
And so we're asked to draw this molecule with all double bonds in the z confirmation.
01:59
So this is all cis double bonds.
02:03
And so that's going to look like this.
02:05
So from our, you know what, here i'll actually, i'll call these a, b, and c.
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Do it in green.
02:13
So a, b, and c.
02:16
So from part a, part a is going to give us this.
02:20
So one, two, three.
02:24
Okay, so there's part a...