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Problem 127 Hard Difficulty

Diagonal of a box. The length of the diagonal of a box $D$ is a function of its length $L,$ width $W,$ and height $H:$
$$D=\left(L^{2}+W^{2}+H^{2}\right)^{1 / 2}$$
a) Find $D$ for the box shown in the accompanying figure.
b) Find $D$ if $L=W=H=1$ inch.

Answer

a) 13 in.
b) $\sqrt{3}$ or 1.73 in.

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Top Algebra Educators
Anna Marie V.

Campbell University

Alayna H.

McMaster University

Kayleah T.

Harvey Mudd College

Kristen K.

University of Michigan - Ann Arbor

Watch More Solved Questions in Chapter 7

Video Transcript

the length of the diagonal for box is given by equal to the square place W square place such as quite the full bore on my do where your missile and the use of it on matches the height. So we need to find the Bagnall, eat off the box in the given figure. So from the even bigger we see that the value of Yeah, it is 12. Yes, this 12 Onda good w is move and hedge iss three Now let us substitute the values over. Yell that you are hatching given when will our d d Well too once well, place was where less the Squire about one way to that is What were you? Yes, 60 s nine About one great. Just remind to you 1 16 91 69 over weight began by 1 69 s 13 in squared for one baking and using the bar off rules it is doing You want a toe just standing there being inches Since the diagonal d off the books shown this 13 inches. Now you need to find the final You really will do w went to work Some students nearly equal to the beauty will do. And she will do one in this given formula. So we get He went to one squad. Bliss one square less. One square. One way to it. ISS one. Yes. One place one over. One way to just 312 The annual keep over 12 iss. We are approximately 1.70 inches.

Other Schools
Top Algebra Educators
Anna Marie V.

Campbell University

Alayna H.

McMaster University

Kayleah T.

Harvey Mudd College

Kristen K.

University of Michigan - Ann Arbor