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Diagonalize the matrices in Exercises $7-20,$ if possible. The eigenvalues for Exercises $11-16$ are as follows: $(11) \lambda=1,2,3$ (12) $\lambda=2,8 ;(13) \lambda=5,1 ;(14) \lambda=5,4 ;(15) \lambda=3,1 ;(16)$ $\lambda=2,1 .$ For Exercise $18,$ one eigenvalue is $\lambda=5$ and one eigenvector is $(-2,1,2) .$$\left[\begin{array}{ll}{5} & {1} \\ {0} & {5}\end{array}\right]$

is not diagonalizable.

Calculus 3

Chapter 5

Eigenvalues and Eigenvectors

Section 3

Diagonalization

Vectors

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were given 5105 Okay, we know, eh? It's causing a is triangular. It's our only idea. Values five and five. Okay, so you have another five minutes to anyone is five I. That gives us there. A one goes out which said steak that X two equal to zero and we have that X one. It's free. So are generous solution Compass. It's one time ones out.

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