Question
Die Extremwerte der Funktion $x^{2}+y^{2}+z$ auf der Menge$$\left.\mid(x, y, z) \in \mathbf{R}^{3}:(x-1)^{2}+y^{2}=5, y=z\right\}$$sind 11 und $1 .$
Step 1
Die Menge ist gegeben durch die Gleichung \( (x-1)^2 + y^2 = 5 \) und die Bedingung \( y = z \). Show more…
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