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Welcome.
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Today we're looking at a function of x and y, y plus xe to the y.
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We're asked to find two integrals using this function.
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The first one, the integral from 0 to 5 of the function, with respect to x.
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So first thing i'm going to do is replace f of xy with the function we're actually given.
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So we're taking the integral from 0 to 5 of y plus xe to the y.
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With respect to x.
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So when we do that, y you can just treat like constant.
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So x, y.
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The second term, x, e to the y, e to the y is just a coefficient.
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So we have one half x squared e to the y, and we have to plug in our zero and our five.
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So i'll start by plugging in the five.
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So five y plus one half 5 squared, e to the y.
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And both of those terms will go to zero when we plug in zero.
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So you don't even have to write that down because you know you're just going to subtract zero at the end.
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So let's simplify this a tiny bit.
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5y plus 25 squared makes 25 over 2, e to the y.
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So that is the answer to the first part of this problem...