00:01
In this question, we have a function fx is equals to ax, cosine, logx plus bx, sine, log x.
00:16
We are required to find its derivative, and with the help of that, we are required to find the integration of cosine log x, dx, and sine logx dx.
00:36
So let's see how to solve this question.
00:40
We know that the differentiation of the product of two functions f1x into f2x is f1 into d by d x of f2x plus second function f2x into differentiation of first function f1 x.
01:05
So based on this formula, now we can find the derivative of f2x.
01:10
So, we can write f -dash x is equals to a into first function that means x into differentiation of second function cos log x plus second function that means cosine log x into differentiation of first function x plus b into first function that means x into first function that means x into differentiation of sine log x plus second function that means sine log x into differentiation of first function that means x we know that the differentiation of sine x with respect to x is cosine x the differentiation of cosine x with respect to x is minus sine x and the differentiation of x to the power n is equal to n x to the power n minus 1.
02:33
So on the basis of these formulas, now we can write f -dash -x is equal to a into x into differentiation of cosine log -x will be equal to minus sine log -x into the differentiation of log -x is equals to 1 upon x plus cosine log x into differentiation of x is equals to 1 plus b into differentiation of sign log x is equal to cosine log x into differentiation of log x is equal to 1 upon x and it is multiplied by x plus sine log x into differentiation of x is equals to 1.
03:30
So when we further calculate this, we get f -dash -x is equal to a cosine log x minus a sine log x plus b sine log x plus b sine log x...