00:01
In this problem, we're told that dianns undergo metathesis, and we're asked to explain how a is converted to b.
00:09
And i've drawn a, b, and c right here.
00:13
So we've got two sigma and two pi bonds are broken.
00:18
Let me switch colors.
00:34
You can see my pie bonds here.
00:38
And they form one alkyne and one alkyne.
00:56
Okay, then it repeats.
01:09
The other alkyne and the same alkyne.
01:23
So that leads to the formation of a fused bicyclic ring.
01:42
Okay.
01:43
So that explains a to b.
01:47
And then we have another part b.
01:51
Let me see what b is.
01:53
Keep this in mind, draw the two products formed by the dye, di -anine metathesis of c.
02:22
And again, there is c.
02:26
And let me get up to that page...