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Numerade Educator



Problem 8 Easy Difficulty


$ f(t) = \frac {cot t}{e^t} $


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Video Transcript

Hey, it's close. So when you raid here, So we're gonna take the derivative of KO 10 gin over E to the T. So we're gonna ply the quotient Roll. First we got a code 10 gin turns B to the T minus D over DT of e to the T oh, tangent all over e to the T Square. This becomes equal to negative coast sequence square terms T turns e to the T minus e to the t co tension over E to the T Square. And this can be simplified too negative Coast seeking square plus co tangent well over feet to the T.