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Numerade Educator

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Problem 21 Easy Difficulty

Differentiate.

$ f(t) = \frac {sqrt[3]{t}}{1 - 3} $

Answer

$\frac{-2 t+3}{3 ( t-3)^{2}t^{2 / 3}}$

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Video Transcript

Hey, it's clear. So when you married here. So we're gonna differentiate this in terms of tea for you. Cube root of tea over T minus three just becomes equal to de over de ti que brood of three t times T minus three minus Q Brood of tea. Do you over DT of T minus three while over T minus three square. We simplify this to get T minus three over three t to the 2/3 power minus one plus zero square root Hubert of tea over T minus three square. We simplify, we get negative to t plus three over three times T minus three square he to the 2/3 power.