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Differentiate.$f(t) = \frac {sqrt[3]{t}}{1 - 3}$

$\frac{-2 t+3}{3 ( t-3)^{2}t^{2 / 3}}$

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Anna Marie V.

Campbell University

Heather Z.

Oregon State University

Kristen K.

University of Michigan - Ann Arbor

Samuel H.

University of Nottingham

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Video Transcript

Hey, it's clear. So when you married here. So we're gonna differentiate this in terms of tea for you. Cube root of tea over T minus three just becomes equal to de over de ti que brood of three t times T minus three minus Q Brood of tea. Do you over DT of T minus three while over T minus three square. We simplify this to get T minus three over three t to the 2/3 power minus one plus zero square root Hubert of tea over T minus three square. We simplify, we get negative to t plus three over three times T minus three square he to the 2/3 power.

Anna Marie V.

Campbell University

Heather Z.

Oregon State University

Kristen K.

University of Michigan - Ann Arbor

Samuel H.

University of Nottingham

Lectures

Join Bootcamp