Problem

Prove that $ \frac {d}{dx}$ (csc $ x $ ) = - csc …

01:20

Problem 16 Medium Difficulty

Differentiate.

$ f(t) = te^t $ cot $ t $

Answer

More Answers

00:54

Frank L.

Topics

Derivatives

Differentiation

Book Cover for Calculus: Early Tra…

Calculus: Early Transcendentals

Chapter 3

Differentiation Rules

Section 3

Derivatives of Trigonometric Functions

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Watch More Solved Questions in Chapter 3

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Video Transcript

Hey, it's clear. So when you reign here so we're gonna take the derivative of tea times eats the tea times coat engine. This becomes equal to D over DT of tea times E to the T Times CO Tension plus T It's clear. So when you reign here so we're gonna times d over DT of each the team coat engine close T U to the T do you over DT of coat engine, which is equal to negative. T you take the derivative of tea times eats the tea times coat engine This becomes equal to D over DT of tea times E to the t Times Co Tension plus t t Co Seacon Square blessed t he to the team ko 10 gin of tea. Plus I mean to the t coat engine of tea you simplify and we get to the times D over DT of each the team coat engine close t u to the t do you over DT of coat engine which is equal to negative t eat t negative e to the t Times t co Sika Square plus negative T minus one co tension

Clarissa N.

Topics

Derivatives

Differentiation

Book Cover for Calculus: Early Tra…

Calculus: Early Transcendentals

Chapter 3

Differentiation Rules

Section 3

Derivatives of Trigonometric Functions

Top Calculus 1 / AB Educators

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