Problem

Prove that $ \frac {d}{dx}$ (csc $ x $ ) = - csc …

01:20

Problem 16 Medium Difficulty

Differentiate.

$ f(t) = te^t $ cot $ t $

Answer

October 8, 2021

y = x8 + cot(x)

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Problem 16

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Video Transcript

Hey, it's clear. So when you reign here so we're gonna take the derivative of tea times eats the tea times coat engine. This becomes equal to D over DT of tea times E to the T Times CO Tension plus T It's clear. So when you reign here so we're gonna times d over DT of each the team coat engine close T U to the T do you over DT of coat engine, which is equal to negative. T you take the derivative of tea times eats the tea times coat engine This becomes equal to D over DT of tea times E to the t Times Co Tension plus t t Co Seacon Square blessed t he to the team ko 10 gin of tea. Plus I mean to the t coat engine of tea you simplify and we get to the times D over DT of each the team coat engine close t u to the t do you over DT of coat engine which is equal to negative t eat t negative e to the t Times t co Sika Square plus negative T minus one co tension

Frank L.

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Problem

Prove that $ \frac {d}{dx}$ (csc $ x $ ) = - csc …

Problem 16 Medium Difficulty

Differentiate.

$ f(t) = te^t $ cot $ t $

Answer

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Related Courses

Calculus: Early Transcendentals

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