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Problem 11 Easy Difficulty


$ f(\theta) = \frac {sin \theta }{1 + cos \theta } $


$$f^{\prime}(\theta)=\frac{(1+\cos \theta) \cos \theta-(\sin \theta)(-\sin \theta)}{(1+\cos \theta)^{2}}=\frac{\cos \theta+\cos ^{2} \theta+\sin ^{2} \theta}{(1+\cos \theta)^{2}}=\frac{\cos \theta+1}{(1+\cos \theta)^{2}}=\frac{1}{1+\cos \theta}$$

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