Problem

Differentiate. $ y = \frac {cos x}{1 - sin x}…

01:46

Problem 11 Easy Difficulty

Differentiate.

$ f(\theta) = \frac {sin \theta }{1 + cos \theta } $

Answer

$$f^{\prime}(\theta)=\frac{(1+\cos \theta) \cos \theta-(\sin \theta)(-\sin \theta)}{(1+\cos \theta)^{2}}=\frac{\cos \theta+\cos ^{2} \theta+\sin ^{2} \theta}{(1+\cos \theta)^{2}}=\frac{\cos \theta+1}{(1+\cos \theta)^{2}}=\frac{1}{1+\cos \theta}$$

Watch More Solved Questions in Chapter 3

Problem 1

Problem 2

Problem 3

Problem 4

Problem 5

Problem 6

Problem 7

Problem 8

Problem 9

Problem 10

Problem 11

Problem 12

Problem 13

Problem 14

Problem 15

Problem 16

Problem 17

Problem 18

Problem 19

Problem 20

Problem 21

Problem 22

Problem 23

Problem 24

Problem 25

Problem 26

Problem 27

Problem 28

Problem 29

Problem 30

Problem 31

Problem 32

Problem 33

Problem 34

Problem 35

Problem 36

Problem 37

Problem 38

Problem 39

Problem 40

Problem 41

Problem 42

Problem 43

Problem 44

Problem 45

Problem 46

Problem 47

Problem 48

Problem 49

Problem 50

Problem 51

Problem 52

Problem 53

Problem 54

Problem 55

Problem 56

Problem 57

Problem 58

Video Transcript

it's clear. Someone name right here. So we're gonna differentiate of if they'd eyes equal to sign beta. Well, everyone plus co sign. We're gonna start with the caution rule, which gives us de over de Feydeau. Sign data was one class is co sign of beta minus. Be over. D fada, have co sign data. I'm signed data well over one plus go sign the U. S. Square. This gives us co sign Data plus co sign square plus sign square over one plus co sign Data Square. This simplifies further to co sign plus one over one plus Go Son Data Square, which is equal to one plus one over one plus post signed data.

Clarissa N.

Related Courses

Calculus 1 / AB

Calculus: Early Transcendentals

Chapter 3

Differentiation Rules

Section 3

Derivatives of Trigonometric Functions

Problem

Differentiate. $ y = \frac {cos x}{1 - sin x}…

Problem 11 Easy Difficulty

Differentiate.

$ f(\theta) = \frac {sin \theta }{1 + cos \theta } $

Answer

$$f^{\prime}(\theta)=\frac{(1+\cos \theta) \cos \theta-(\sin \theta)(-\sin \theta)}{(1+\cos \theta)^{2}}=\frac{\cos \theta+\cos ^{2} \theta+\sin ^{2} \theta}{(1+\cos \theta)^{2}}=\frac{\cos \theta+1}{(1+\cos \theta)^{2}}=\frac{1}{1+\cos \theta}$$

More Answers

Related Courses

Calculus: Early Transcendentals

Related Topics

Discussion

Top Calculus 1 / AB Educators

Anna Marie V.

Heather Z.

Caleb E.

Samuel H.

Calculus 1 / AB Courses

Precalculus Review - Intro

Functions on the Real Line - Overview

Recommended Videos

Watch More Solved Questions in Chapter 3

Video Transcript

Calculus: Early Transcendentals

Anna Marie V.

Heather Z.

Caleb E.

Samuel H.

Precalculus Review - Intro

Functions on the Real Line - Overview