Problem

Differentiate. $ f(z) = (1 - e^z)(z + e^z) $

01:16

Problem 11 Easy Difficulty

Differentiate.

$ F(y) = \left (\frac {1}{y^2} - \frac {3}{y^4} \right)(y + 5y^3) $

Answer

$\frac{5 y^{4}+14 y^{2}+9}{y^{4}}$

Discussion

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Milton S.

March 3, 2021

im confused as to why the equation has to be extended so much and how u get to the last step ?

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Video Transcript

he It's clear. So when you read here So we're gonna take the derivative. Do you ever do Y won over Y square minus three over y to the fourth comes five. Why cubes? Plus why this becomes equal to D over d. Y won over. Do you won over Wife Square minus three over whites The fourth by like you Plus why less one over Why square minus three over y to the fourth Do you over? Do you? Why? By why Q plus. Why, then this becomes equal to negative, too. Why? To the negative cubes minus three times negative four. Why'd the negative five five y que plus why close by times three Wives Square plus one won over Wife Square minus three over wide to the fourth. When you simplify, you get by y to the fourth plus 14 Wise Square plus nine over Y to the fourth.

Clarissa N.

Topics

Derivatives

Differentiation

Calculus: Early Transcendentals

Chapter 3

Differentiation Rules

Section 2

The Product and Quotient Rules

Problem

Differentiate. $ f(z) = (1 - e^z)(z + e^z) $

Problem 11 Easy Difficulty

Differentiate.

$ F(y) = \left (\frac {1}{y^2} - \frac {3}{y^4} \right)(y + 5y^3) $

Answer

$\frac{5 y^{4}+14 y^{2}+9}{y^{4}}$

More Answers

Topics

Calculus: Early Transcendentals

Discussion

Top Calculus 1 / AB Educators

Anna Marie V.

Kayleah T.

Caleb E.

Kristen K.

Calculus 1 / AB Bootcamp

Precalculus Review - Intro

Functions on the Real Line - Overview

Recommended Videos

Watch More Solved Questions in Chapter 3

Video Transcript

Topics

Calculus: Early Transcendentals

Top Calculus 1 / AB Educators

Anna Marie V.

Kayleah T.

Caleb E.

Kristen K.

Calculus 1 / AB Bootcamp

Precalculus Review - Intro

Functions on the Real Line - Overview

Recommended Videos

Problem

Differentiate. $ f(z) = (1 - e^z)(z + e^z) $

Problem 11 Easy Difficulty

Differentiate. $ F(y) = \left (\frac {1}{y^2} - \frac {3}{y^4} \right)(y + 5y^3) $

Answer

$\frac{5 y^{4}+14 y^{2}+9}{y^{4}}$

More Answers

Topics

Calculus: Early Transcendentals

Discussion

Top Calculus 1 / AB Educators

Anna Marie V.

Kayleah T.

Caleb E.

Kristen K.

Calculus 1 / AB Bootcamp

Precalculus Review - Intro

Functions on the Real Line - Overview

Recommended Videos

Watch More Solved Questions in Chapter 3

Video Transcript

Topics

Calculus: Early Transcendentals

Top Calculus 1 / AB Educators

Anna Marie V.

Kayleah T.

Caleb E.

Kristen K.

Calculus 1 / AB Bootcamp

Precalculus Review - Intro

Functions on the Real Line - Overview

Recommended Videos

Differentiate.

$ F(y) = \left (\frac {1}{y^2} - \frac {3}{y^4} \right)(y + 5y^3) $