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Numerade Educator

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Problem 7 Easy Difficulty

Differentiate the function.
$ f(t) = 2t^3 - 3t^2 - 4t $

Answer

$$f^{\prime}(t)=2\left(3 t^{2}\right)-3(2 t)-4(1)=6 t^{2}-6 t-4$$

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Video Transcript

it's clear, says So. I'm gonna differentiate the function D over DT in terms of tea to t cute minus three T Square minus 40. This is equal to two three tea three minus one minus three times to t to the two minus one minus four T one minus one. That gives us 60 square minus 60 minus four.