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# Differentiate the function.$f(v) = \frac{\sqrt[3]{v - 2ve^v}}{v}$

## $$f^{\prime}(v)=-\frac{2}{3} v^{-5 / 3}-2 e^{u}$$

Derivatives

Differentiation

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JR

Jp R.

October 17, 2019

what kind of transcript is this? Seriously?!

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### Video Transcript

he had slurs. So when you read here so agree. Right fo fee as be too negative. 2/3 minus to eat the V. We used the some indifference full. When we get d over a devi B to the negative 2/3 my honesty over Devi to eat to the V then used to constant multiple room take up to then the power roll. So we get negative 2/3 fee to the negative 2/3 minus one minus two eats the V. We get negative 2/3 the to the negative 5/3 minus two e to the t.

Derivatives

Differentiation

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