Problem

Differentiate the function. $ S(R) = 4\pi R^2 $

00:46

Problem 19 Easy Difficulty

Differentiate the function.
$ y = 3e^x + \frac{4}{\sqrt[3]{x}} $

Answer

$$y^{\prime}=3\left(e^{x}\right)+4\left(-\frac{1}{3}\right) x^{-4 / 3}=3 e^{x}-\frac{4}{3} x^{-4 / 3}$$

Discussion

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Problem 18

Problem 19

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Video Transcript

he It's clear. So when you right here. So we're gonna start with different shooting the function in terms of X. So we have three feet X plus four over X to the one negative 1/3 power. Oh, this becomes equal to D over d x three each the X plus de over DX four bucks to the negative 1/3 power. We're gonna apply the power rule to get 38 x close negative 1/3 terms for X to the negative 4/3. This becomes equal to three feet X minus 4/3 x to the negative 4/3.

Clarissa N.

Topics

Derivatives

Differentiation

Calculus: Early Transcendentals

Chapter 3

Differentiation Rules

Section 1

Derivatives of Polynomials and Exponential Functions

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Problem

Differentiate the function. $ S(R) = 4\pi R^2 $

Problem 19 Easy Difficulty

Differentiate the function.
$ y = 3e^x + \frac{4}{\sqrt[3]{x}} $

Answer

$$y^{\prime}=3\left(e^{x}\right)+4\left(-\frac{1}{3}\right) x^{-4 / 3}=3 e^{x}-\frac{4}{3} x^{-4 / 3}$$

More Answers

Topics

Calculus: Early Transcendentals

Discussion

Top Calculus 1 / AB Educators

Anna Marie V.

Kristen K.

Samuel H.

Joseph L.

Calculus 1 / AB Bootcamp

Precalculus Review - Intro

Functions on the Real Line - Overview

Recommended Videos

Watch More Solved Questions in Chapter 3

Video Transcript

Topics

Calculus: Early Transcendentals

Top Calculus 1 / AB Educators

Catherine R.

Caleb E.

Kristen K.

Joseph L.

Calculus 1 / AB Bootcamp

Precalculus Review - Intro

Functions on the Real Line - Overview

Recommended Videos

Problem

Differentiate the function. $ S(R) = 4\pi R^2 $

Problem 19 Easy Difficulty

Differentiate the function.$ y = 3e^x + \frac{4}{\sqrt[3]{x}} $

Answer

$$y^{\prime}=3\left(e^{x}\right)+4\left(-\frac{1}{3}\right) x^{-4 / 3}=3 e^{x}-\frac{4}{3} x^{-4 / 3}$$

More Answers

Topics

Calculus: Early Transcendentals

Discussion

Top Calculus 1 / AB Educators

Anna Marie V.

Kristen K.

Samuel H.

Joseph L.

Calculus 1 / AB Bootcamp

Precalculus Review - Intro

Functions on the Real Line - Overview

Recommended Videos

Watch More Solved Questions in Chapter 3

Video Transcript

Topics

Calculus: Early Transcendentals

Top Calculus 1 / AB Educators

Catherine R.

Caleb E.

Kristen K.

Joseph L.

Calculus 1 / AB Bootcamp

Precalculus Review - Intro

Functions on the Real Line - Overview

Recommended Videos

Differentiate the function.
$ y = 3e^x + \frac{4}{\sqrt[3]{x}} $