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Numerade Educator

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Problem 19 Easy Difficulty

Differentiate the function.
$ y = 3e^x + \frac{4}{\sqrt[3]{x}} $

Answer

$$y^{\prime}=3\left(e^{x}\right)+4\left(-\frac{1}{3}\right) x^{-4 / 3}=3 e^{x}-\frac{4}{3} x^{-4 / 3}$$

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Video Transcript

he It's clear. So when you right here. So we're gonna start with different shooting the function in terms of X. So we have three feet X plus four over X to the one negative 1/3 power. Oh, this becomes equal to D over d x three each the X plus de over DX four bucks to the negative 1/3 power. We're gonna apply the power rule to get 38 x close negative 1/3 terms for X to the negative 4/3. This becomes equal to three feet X minus 4/3 x to the negative 4/3.