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Numerade Educator

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Problem 23 Easy Difficulty

Differentiate the function.
$ y = \frac {x^2+4x+3}{\sqrt{x}} $

Answer

$$\frac{3 x^{2}}{2 x \sqrt{x}}+\frac{4 x}{2 x \sqrt{x}}-\frac{3}{2 x \sqrt{x}}=\frac{3 x^{2}+4 x-3}{2 x \sqrt{x}}$$

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Video Transcript

he It's clear. So when you read here, so we have. Why is equal to X Square plus four X plus three over square root of acts. This is equal to X to the three house plus four x to the one have plus three X to the negative 1/2. When we differentiate this, we do it in terms of D over T X and then we're going to take the power role for a differentiation. So he could three halves next to the three halves minus one plus four comes 1/2 ex. The one have minus one plus three times negative one have X negative 1/2 minus one, and this becomes equal to three. Have X to the 1/2 plus two x to the negative 1/2 minus three. Have X It's the negative. Three Have