Problem

Differentiate. $ y = (z^2 + e^z)\sqrt{z} $

01:18

Problem 19 Easy Difficulty

Differentiate.

$ y = \frac {s - \sqrt{s}}{s^2} $

Answer

$\frac{-2 \sqrt{s} - 3}{2s^{5 / 2}}$

More Answers

00:24

Frank L.

Topics

Derivatives

Differentiation

Book Cover for Calculus: Early Tra…

Calculus: Early Transcendentals

Chapter 3

Differentiation Rules

Section 2

The Product and Quotient Rules

Discussion

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Watch More Solved Questions in Chapter 3

Problem 1

Problem 2

Problem 3

Problem 4

Problem 5

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Video Transcript

he It's clear. So when you read here, so we're gonna find it The derivative in terms of gas for s minus square root of us over square. This is equal to D over D s. There s minus square root of us times square minus less minus squared of us. Do you Over D s, that's square all over a square square. This becomes equal to one minus square of s 1/2 minus one square s square, minus two s. Come s minus. Grow rude of us over us to the fourth. Normally simplify, we get one minus one over two square root of us times square minus to us s minus square. Root of us over as to the fourth, which is equal to negative to square of pass minus three over to s to the 5/2 power

Clarissa N.

Topics

Derivatives

Differentiation

Book Cover for Calculus: Early Tra…

Calculus: Early Transcendentals

Chapter 3

Differentiation Rules

Section 2

The Product and Quotient Rules

Top Calculus 1 / AB Educators

Grace H.

Numerade Educator

Catherine R.

Missouri State University

Anna Marie V.

Campbell University

Heather Z.

Oregon State University