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Numerade Educator

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Problem 5 Easy Difficulty

Differentiate.

$ y = $ sec $ \theta $ tan $ \theta $

Answer

$$y^{\prime}=\sec \theta\left(\sec ^{2} \theta\right)+\tan \theta(\sec \theta \tan \theta)=\sec \theta\left(\sec ^{2} \theta+\tan ^{2} \theta\right)$$

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Video Transcript

Hey, it's clear. So when you right here. So we have Why equal? Seek it. Data engine data. We're gonna use the product rule when we get secret. Data D Over. He stayed up of 10 plus Tangent data D over deed. Saito, who's seeking yes equals sequence square and seeking becomes seeking times 10 gin. So that's equal seeking Cubed plus seeking times 10 gents square.