00:01
Okay, so we have the following equilibrium expression here.
00:04
This is c, and they want us to find the percentage of acetic acid that is converted to a diameter.
00:11
They tell us kc is 3 .2 times 10 to the 4, and they tell us the initial concentration of acetic acid is 5 .4 times 10 to the negative 4, right? so let's fill in the ice table we have here.
00:26
So we have initial concentration is 5 .4 times 10 to the negative 4.
00:31
And we know the initial concentration of the dimer is zero, right? because no acetic acid has form a dimer yet at time equals zero.
00:40
Now what is the change? well, the change in acetic acid is minus 2x and the change in the dimer is x.
00:47
Why is this? well, because if we look at this, we have two moles of ch3, co2h, like we have two moles of acetic acid and we only have one mole of dimer.
00:56
So every two moles of acetic acid that disappears, we get one mole of dimer.
01:02
So let's write the equilibrium expression.
01:05
We get 5 .4 times 10 to the negative 4 minus 2x and then we get 0 plus x which is just x.
01:13
Now we have enough information to solve for x, right? so we have k is equal to the concentration of the product over the concentration of the reactant...