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Dimethyl sulfoxide $\left[\left(\mathrm{CH}_{3}\right)_{2} \mathrm{SO}\right],$ also called DMSO, is an important solvent that penetrates the skin, enabling it to be used as a topical drug-delivery agent. Calculate the number of $\mathrm{C}$S, H, and O atoms in $7.14 \times 10^{3} \mathrm{g}$ of dimethyl sulfoxide.

The number of $C$ atoms is $1.10 \cdot 10^{26}$ The number of $\mathrm{H}$ atoms is $3.30 \cdot 10^{26}$ The number of $S$ atoms is $0.55 \cdot 10^{26}$ The number of O atoms is $0.55 \cdot 10^{26}$

Chemistry 101

Chapter 3

Mass Relationships in Chemical Reactions

Chemical reactions and Stoichiometry

Carleton College

University of Maryland - University College

Lectures

04:02

A chemical reaction is a process that leads to the transformation of one set of chemical substances to another. Chemical reactions can be either spontaneous, requiring no input of energy, or non-spontaneous, typically following the input of some type of energy, such as heat, light or electricity. Chemical reactions are usually characterized by a chemical change, and they yield one or more products after the reaction is complete. Chemical reactions are described with chemical equations, which symbolically present the starting materials, end products, and sometimes intermediate products and reaction conditions. Chemical reactions happen at a characteristic reaction rate at a given temperature and chemical concentration. Typically, reaction rates increase with increasing temperature because there is more thermal energy available to reach the activation energy necessary for breaking bonds between atoms.

08:02

In chemistry, a combination reaction is a chemical reaction in which two or more reactants combine to form more than one product. In a decomposition reaction, one reactant splits into two or more products.

01:38

Dimethyl sulfoxide (DMSO) …

02:11

Dimethylsulfoxide (DMSO) i…

01:35

Methyl ethyl ketone, $\mat…

03:16

Cyclopropane, a gas that w…

01:36

The molecular formula of s…

01:29

MOLECULAR FORMULASThe …

So in this question, we are given this were given dimethyl. So Fox, I'm sure here and were asked to calculate the number of sea carbon, sulfur, hydrogen and oxygen atoms. There are in 7.14 times 10 to the three grams. So in order to do this, we first need to calculate the molar mass of dimethyl solve oxide. So to do this and we're going to first look at the periodic table to find the molar mass of each Adam. So we have carbons right here. Sulfur, hydrogen and oxygen. So we're gonna start with carbon, so we have to carbon. So what we need to do is take 12 times two, and we're gonna add that to we have six hydrogen ins, so we're gonna dio one times six and then we're gonna add that to one sulfur, which is 32. We're gonna add that to one oxygen, which is 16. And when we end this together we get the molar mass of di mezzo saw Fox. Time is 78th grams per mole. So now we have that and we need to figure out First of all, how many moles of this dimethyl a soft walk side. Do we have? So we're told that there seven seven points 14 times 10 to the three grands and reconvert. That's moles on with some dimensional analysis. We know that we have 78 grams and one more. Sorry about that one. And if we multiply these together or rather, divide by 78 we get that there are 91.5 moles. Dimethyl sof oxide. Okay, great. So now we have that. Okay, I'm just going over your rights. I'm Ethel Saw Fox. I'd here, so we know the formula. See age three to s o. Okay. Now what we need to do is figure out the moles of each of these Adams, So see, age us. And, uh oh, how many moles of that are within one of these compounds? So, for instance, if we have, we have one more of this, this whole thing. So one more of ch 32 eso. Okay, so within that, how many moles of carbon do we have? So if we have one more of this, we know that one more of this whole thing goes to two moles of carbon because there are two carbons. So we actually have two moles. So now if we go back to our molar mass up here, we know that we have a total of 91.5 moles of our whole thing. And we know that one mole of a roll thing goes to two moles, Carmen. And now we know that one more carbon equals 6.0 to 2 times 10 23 molecules. So when we calculate that together, we get that there are 1.1 times 10 to the 26 molecules of carbon, and now we're going to follow the same process for the other ones. So we're starting out with 91.5 moles. And, um so for hydrogen, we know that there are 600 Jin's in our whole compound, so we know that there's one more close to six moles of hydrogen and we go to are ratio of molecules to malls. You know that one more H equals 6.2 to 10. The 23 and her answer is going to be 3.3 times 10 to the sixth molecules of car of hydrogen. Sorry about that. Okay. Finally, for our last two. Our last two are gonna be the same cause there's one Adam within the entire molecule. So we got 91.5. Moles are whole thing, and we know that within our compound within one mole of our compound there is one mole, uh, s sulfur or oxygen. So this is the same for both of those Adams and Wilson on that one. More because 6.0 to 2 times 10 to the 23 molecules. Okay, so if you can't calculate those three other, we get 0.55 times 10 26 molecules of either suffer or oxygen.

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