00:01
In this question, we are calculating the enthalpy of reaction, and the reaction is the decomposition of di -nitrogen dioxide into nitrogen gas and oxygen gas.
00:12
Now, the first step to solving a question like this is to draw out the structures so that you know which bonds you're breaking and which ones you're making.
00:22
So the structure of dinitrogen oxide is nitrogen, triple bond to the other nitrogen.
00:31
Single bonded to the oxygen.
00:35
Now there are other possible resonance structures, but if you check your formal charges, you'll find that this one is the most favorable.
00:43
And we're going to draw it again because there's two of them.
00:54
And that's going to turn into nitrogen gas, which looks like this, and we have two of those two, and oxygen gas, which will look like this.
01:17
So from a lot of an energetic standpoint, we are breaking these bonds, we are making these bonds.
01:28
So let's get to the math part.
01:32
The enthalpy of this reaction is delta h of the reaction is equal to the energy required to break the bonds.
01:46
So that is, i'm just going to say, break, plus the energy.
01:54
Energy associated with making the bonds.
02:00
And different equations from different textbooks will use different signs, but i'll guide you through that in just a moment.
02:08
So let's start with calculating out breaking the bonds.
02:15
First up, we have this nitrogen -nitrogen bond.
02:20
It takes energy to break bonds.
02:24
So, and we know from our table that the nitrogen -nitrogen -nitrogen bond.
02:28
Nitrogen bond has 945 kilojoules, or it'll take that much to either break or form.
02:38
So we have 945, and it's a positive because breaking bonds requires energy.
02:51
Then we also have to break this nitrogen and oxygen bond, and that value is 201 kilojoules.
02:59
And since we have two of them, we're going to multiply this by two.
03:06
Next, we have to make two of these nitrogen gas bonds.
03:12
That's same nitrogen, nitrogen, triple bond...