Question
Dinitrogen pentoxide is an ionic compound formed from the ions $\mathrm{NO}_{2}^{+}$ and $\mathrm{NO}_{3}^{-}$. Give the oxidation state of $\mathrm{N}$ in each ion and the VSEPR shape for each of the ions.
Step 1
Determine the oxidation state of N in each ion: In NO2+ ion: - Oxygen has an oxidation state of -2. - There are two oxygen atoms, so the total oxidation state of oxygen in the ion is -4. - The ion has a charge of +1, so the oxidation state of N in NO2+ must be +3 Show more…
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Dinitrogen pentoxide, $\mathrm{N}_{2} \mathrm{O}_{5},$ when bubbled into water can form nitric acid. Its skeleton structure has no $\mathrm{N}-\mathrm{N}$ or $\mathrm{O}-\mathrm{O}$ bonds. Write its Lewis structure.
Draw a Lewis structure for nitrogen pentoxide $\left(\mathrm{N}_{2} \mathrm{O}_{5}\right)$ in which each $\mathrm{N}$ is bonded to three $\mathrm{O}$ atoms.
Write the Lewis structure for each of the following species, describe its geometry, and indicate the oxidation state of the nitrogen: (a) $\mathrm{NH}_{4}^{+},(\mathbf{b}) \mathrm{NO}_{2}^{-},(\mathbf{c}) \mathrm{N}_{2} \mathrm{O},(\mathbf{d}) \mathrm{NO}_{2}$
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