00:01
Problem 93 asks us to actually create our own rational expressions from some given criteria.
00:10
So the first situation is they're saying the only thing you need to make sure you have is that the vertical asymptote is x equals three.
00:25
Okay.
00:26
So from our experience, we should know that that has to deal with the denominator and the answer to the question of what makes the bottom.
00:33
Zero needs to be three.
00:36
So the easiest way to express that is just put x minus three.
00:39
As far as the numerator, it could be really anything except for x minus three.
00:46
Because if you put x minus three, it'll cancel with the x minus three on bottom.
00:51
So the simplest thing to put with just to be to make up some number and throw in there.
00:56
So our function could be something like one over x minus three.
01:01
Okay, the second situation, they say again, let's say the vertical asymptote is x equals 3, but now we need to have a horizontal asymptote of y equals 2.
01:18
Okay, so with vertical asymptote, we know that the denominator could be x minus 3.
01:25
With the horizontal asymptote, that has to deal with the degrees of the numerator and denominator comparatively.
01:33
The only way to get a number is when the degrees are the same, so that we need this to be x.
01:43
And to get two, we need the ratio of these two leading coefficients to be two.
01:48
So we could throw it to a top there.
01:51
Now the ratio of these leading coefficients is two over one, which is two.
01:55
Now, you could certainly add a number in here plus some number.
01:59
I'll just put b.
02:01
The only thing you could not do, again, is you would not want this numerary to be factored so that you have x minus three up top, which would cancel.
02:09
So b could not be negative 6, because then that could be factored as 2, x minus 3, the x minus 3 is cancel...