00:01
All right, for this question, it's really just a discussion question.
00:03
So we're going to talk about it instead of writing really anything down.
00:06
So we want to use the definition of a determinant, and the elementary row and column operations we know to explain why the matrices of long types have a determinant in zero.
00:14
So with a, i think it's quite clear.
00:17
When you have a matrix with a row or column consisting entirely of zeros, we know from doing our expansion method of finding a determinant.
00:23
If we use a row with all zeros, of course, it's going to clearly give us a determinant of zeros.
00:28
So it's just a, when we have a, a row of zeros column of zeros as soon as we started doing expansion we know the terminate it's going to be zero so for a it's quite obvious for b we have a matrix with two rows the same or two columns the same now this is pretty much the same idea because we can do row and column operation so if we just subtract those two rows or we subtract one of those rows from the other or subtract one of the columns from the others we're going to end up with a zero column or a zero row and then when we do our expansion on that matrix that we've manipulated the determinant is going to be the same as the matrix before we did the row operation, the column operation.
01:02
And so now we have a row or column with all zeros.
01:05
By the same logic of a, when we have that row or column with all zeros, when we take the determinant, it's going to, of course, also be zero...