00:01
That's what we have a preparation and review the virus.
00:11
Alright, so we have 10 plus we squared all over 1 plus b.
00:21
It's somewhere between 0 and 9.
00:25
Alright, so you want to find the maximum and minimum values for this equation.
00:31
So the way we're going to do that is we're going to take the derivative of p.
00:34
Um whoops there we go all right so um remember that the equation rule is u d prime i'm sorry i said that wrong u prime v minus u v divided by um v squared all right then we get see this is u v then we get 2v plus 1 times v which is 1 v plus 1 minus v squared plus v plus 10 times v prime which is just 1 divided by b squared so v plus 1 squared let's simplify that just a little bit or make our lives a little easier so we're going to use foil method here right that's 2 v squared squared plus 2v plus v plus 1 minus v squared minus v minus 10 all over v squared plus 2v actually we're going to hold off on that just for let me see if something nice cancels out i'm not sure it will but that doesn't stop me from hoping it will um all right that's going to cancel that a little bit so we're going to get a b squared plus v, oh, plus 2b, sorry.
02:36
And then it looks like that's going to equal negative, negative 9.
02:46
Is that right? yeah, i think that's right.
02:49
Okay.
03:01
All righty then.
03:05
What can we do from here? well, now that we have that, we can plug in 0 for p prime.
03:13
0 is equal to v squared plus 2b minus 9, b squared plus 2v plus 1.
03:21
And we can start solving for, we can start solving for v.
03:25
So we're going to multiply both sides by denominator here.
03:28
That kind of turns a lot of stuff into 0, actually.
03:32
V squared plus 2v minus 9.
03:36
All right.
03:37
And i can't think of a nice, easy way to factor that.
03:44
So it looks like we're going to have to use the quadratic formula, which is negative b.
03:53
So that's negative 2 plus or minus the square root of b squared minus 4 times a times c all over 2a, which is, oops, it's just one...