00:01
So here, the angular acceleration required to stop the wheel.
00:04
We could use rotational kinematics.
00:06
This would be equal to the change in the angular frequency divided by the change in time.
00:11
This would be equaling to the final angular frequency minus the initial angular frequency divided by the time interval.
00:17
So this would be the final angular frequency would require to be zero.
00:21
This is equaling then negative 900 multiplied by 2 pi, multiplied by 1 .5.
00:34
Over 60 and this would of course just be radiance per second divided by 5 .0 seconds.
00:43
And so alpha, the angular acceleration, would need to be negative 18 .85 radians per second squared.
00:53
And so each brake pad applies a kinetic frictional force, equaling the coefficient of kinetic friction multiplied by the normal force.
01:02
So given this, the normal force is equal to the force applied by the piston.
01:09
This is due, of course, to newton's third law...